CHAPTER 5:
QUANTITATIVE METHODS USED IN HUMAN RESOURCES
Overview: An overview
of the basic quantitative methods human resource personnel rely upon
to administer compensation and benefits programs.
Corresponding courses:
09 Basic Quantitative Methods
19 Quantitative Methods Used in Salary Administration
29 Quantitative Methods Used in Executive Compensation
39 Quantitative Methods Used in Discrimination Analyses
49 Regression Analyses Used in Compensation Administration
59 Quantitative Methods Used in Benefit Administration
MATHEMATICAL SYSTEMS
Most human resource practitioners realize
in an intuitive way that they are using a mathematical system when they
apply quantitative methods, but probably most would not be able to say
what the actual system is. A mathematical system depends on:
-
A set of
elements (such as rational numbers, whole numbers, etc.)
-
Operations that
can be applied to the set of elements (such as addition, multiplication,
etc.)
-
One or more
relationships (such as the equation: 1 + 1 = 2)
-
Axioms that are
accepted rules (e.g., the rule of identity which is expressed in the
equation a = a)
While any system can be used, and human
resource practitioners are accustomed to the simple rules and operations
of the arithmetic system of real numbers, statistical practices often
require the application of special rules and operations within the set of
rules of the mathematical system. In a sense, that makes the statistical
methods, a "subset" of the entire mathematical system that we use. This is
essential to remember since statistical methods cannot exceed the
limitations of normal mathematical boundaries. It is also important to
remember that not all the tests or approaches may be appropriate, because
the boundaries of normal mathematics might be exceeded in given
situations.
In statistics, these boundaries are called
assumptions.1
Mathematical Systems Example
What are the assumptions that a normal
statistical review (e.g., bell-shaped curve) might require in comparing
the results of performance appraisals between men and women in your
organization?
Mathematical Systems Solution
-
The
observations must be independent. That is, one measurement should not
bias the other.
-
The
measurements must be from a normally distributed population. That is,
the traditional "bell-shaped" curve.
-
The populations
must have the same variance (explained later).
-
The measurement
must be of at least an interval scale (also to be explained).
-
The effects
must be additive.
Without more detailed information, the
example of appraised measurement exceeds all these boundaries.2
TYPES OF MEASUREMENTS
There are four basic kinds of measurements:
- Nominal
- Ordinal
- Interval
- Ratio
Nominal Measurements
The first of these, nominal measurements
(or scales) are composed of numerical values that serve to identify
discrete categories; i.e., the numbers are labels for the categories and
imply no quantitative (measurable) differences that can be handled
meaningfully in numerical operations. The numbers on front doors, for
instance, constitute such a scale; Social Security numbers are another
example.
In salary surveys, the numbering of
positions or companies is just such a scale; the numbers are used merely
as labels.
| COMPANY NAME |
COMPANY NUMBER |
POSITION |
POSITION NUMBER |
SALARY* |
| ABC Company |
021 |
Secretary |
91 |
$24,000 |
| ABC Company |
021 |
Clerk |
92 |
$22,000 |
| ABC Company |
021 |
Typist |
93 |
$16,000 |
| XYZ Company |
043 |
CEO |
11 |
$166,000 |
| XYZ Company |
043 |
Clerk |
92 |
$18,000 |
* The numbers are used for illustration
purposes only.
Nominal measurements example
You are about to conduct a survey of five
positions, and you have numbered them as follows:
POSITION |
POSITION # |
Secretary |
1 |
Stenographer |
4 |
Clerk |
2 |
Typist |
5 |
CEO |
3 |
What significant computations can be
completed using the position numbers?
Nominal measurements solution
No SIGNIFICANT computations can be
completed.
For example: 1 + 2 + 3 + 4 + 5 = 15 means
nothing.
Nominal measurements allow only the most
limited application. For example, one can count classes (the numbers of
positions numbered "2" for instance). Or "Yes" - "No" can be counted where
0 - 1 correspond to "yes" and "no." However, most human resource
administrators will find that using nominal measurements in any kind of
mathematical operation is bound to lead to error. For instance:
|
Employee's Social Security Number: |
536-41-3760 |
| |
+ |
Spouse's Social Security Number:
|
437-28-5621
|
|
TOTAL: |
973-69-9381 |
is a totally meaningless number.
Ordinal Measurements
Ordinal measurements have, in addition to
nominal properties, rank differences. That is, the numerical value of
these scales indicates that there are not only differences between
categories but that these are quantifiable differences. An ordinal scale
ranks "observations" with regard to the extent to which they possess more
or less of a given quality. The ranks do not, however, indicate the degree
of difference (how much more or less) of the property each observation
has.
There are events with dimensions that
cannot be readily quantified. It would be absurd to state that a painting
is twice as beautiful as another or that one restaurant has food one-third
as tasty as another. For this reason, ordinal scales are often applied to
observed events that differ along qualitative rather than quantitative
dimensions (especially when the qualitative dimension cannot be easily
expressed quantitatively).
For example, in job evaluation plans, the
following factors cannot be easily broken down into quantifiable units.
Can one job have two times as much the
problem complexity as another? But within each factor there can be a
breakdown of steps.
For example, problem complexity might be
broken down by:
RANK # |
RANK |
1 |
Repetitive |
2 |
Moderately Complex |
3 |
Very Complex |
4 |
Extremely Complex |
These steps may be described as "ordinally
ranked."
Ordinal measurements example
You have been asked to estimate the average
salaries of individuals within the United States who hold the following
degrees:
Ordinal measurements solution
Average salaries by degree:
| DEGREE |
SALARY* |
| PhD |
$61,891 |
| MBA |
$82,463 |
| BS |
$50,438 |
| BA |
$47,625 |
| High School Diploma |
$31,112 |
*The numbers are used for illustration
purposes only.

This measurement is very
important. Performance appraisals are almost always on ordinal scales, yet
human resource practitioners often try to utilize mathematical tests and
computations that require more stringent assumptions.
Interval Measurements
Interval scales are equal unit
scales; that is, the distance between adjacent units on an interval scale
is the same, irrespective of the magnitude of the adjacent scale
units. For instance, the distance between $5,000 and $6,000 is the same as
the distance between $61,000 and $62,000, since it reflects a measurable
increase in real dollars.
Interval scales, however, are
only relative. For example, if these amounts ($5,000 - $6,000 and $61,000
- $62,000) were to represent sales compensation, the amount of actual
sales required to produce the increase in sales compensation in the above
example may be different at $5,000 (to $6,000) and $61,000 (to
$62,000). Thus, the dollar scale may reflect relative rather than
absolute changes. For example:
SALES ($) |
BROKER'S COMMISSION ($) |
SALESMAN'S COMMISSION ($) |
20,000 |
0 |
0 |
40,000 |
500 |
300 |
60,000 |
1,500 |
900 |
120,000 |
4,500 |
2,700 |
Interval scales are the most
frequently used measurement in human resource pay practices. However,
many human resource measurements cannot satisfy the requirements that
measurements be similar and equidistant in their measurement
intervals. Their ordinal or nominal characteristics must be recognized in
order to understand the explanations of tests discussed later in this
chapter.
Interval measurements
example
A salesman sells a product for
$90,000. His employing broker's commission is 5% after the first $30,000.
The salesman receives 60% of this broker's commission. What is the
salesman's commission?
Interval measurements
solution
Salesperson's commission:
Revenue - Base = Commissionable Revenue
$90,000 - $30,000 = $60,000
Commissionable Revenue x Broker's Percentage = Total Commission
$60,000 x 0.05 = $3,000
Total Commission x Salesman's Percentage = Salesman's Commission
$3,000 x 0.60 = $1,800
Special note:
These plans are often increased or decreased in specific percentage
amounts for:
-
special product mix
-
new client solicitation
-
new market or product
introduction
-
administrative effectiveness
-
other variables
Salesmen operate (and are
motivated) on ordinal rates via interval increases.
Ratio Measurements
The ratio scale has, in
addition to the properties of the nominal, ordinal and interval scales, an
absolute zero. The absolute zero represents a point below which no value
can be assigned. Zero represents no less than one of the property being
gauged by the scale. In salary administration, for example, dollars in
value can be shown on the interval scale, while percentages can be shown
on a ratio scale. Compensation dollars, however, can be ratio ( i.e., if
no negative exists).
(One must remember that
division by zero is not an acceptable mathematical operation. Hence, ratio
measurements have certain computational limitations.)
Examples of ratio measurements
include:
SALES ($)
$0 Base |
EXPENSES ($)
$0 Base |
EXPENSE RATIO
$0 Base |
| 1,000,000 |
Rent = 5,000 |
0.5% |
| Travel = 50,000 |
5.0% |
| Salaries = 500,000 |
50.0% |
| Benefits = 175,000 |
17.5% |
Ratio measurements example
You have three departments,
each of which has budgeted the following salary increases for the coming
year:
Department A: 7% raise for 2
employees
Department B: 9% raise for 3 employees
Department C: 11% raise for 95 employees
All employees are receiving
$10,000 annual base salaries.
What is the overall budgeted
salary increase for the coming year?
Ratio measurements solution
All individuals receive
$10,000/year salaries.
| DEPT. |
#
OF EMPLOYEES |
%
INCREASE |
TOTAL
BASE SALARY ($) |
TOTAL
SALARY INCREASE ($) |
| A |
2 |
7 |
20,000 |
1,400 |
| B |
3 |
9 |
30,000 |
2,700 |
| C |
95 |
11 |
950,000 |
104,500 |
| TOTAL |
100 |
27 |
1,000,000 |
108,600 |
Overall increase of salary budget = $108,600 / (100 x $10,000)
Overall increase of salary budget = 10.86%
NOT
Overall increase of salary budget = 27 + 3
Overall increase of salary budget = 9%
This example is designed to illustrate a
common error in human resource administration: addition and division of
ratios. "Averaging averages" rarely works. As shown above, 9% is not the
overall percentage of salary increase because of the equal weight given to
departments rather than individuals.
The real average is determined by adding
the values of the variables (increases) for all 100 observed events and
then dividing that correctly by the number of observations (the total base
employees' salaries).
FOUR BASIC MATHEMATICAL OPERATIONS
The basic "statements" of operations in
mathematics are statements of equality or inequality. The operation
performed on a number or group of numbers is designed to reduce the value
to a single number (essentially, to simplify).
The four most common mathematical
operations are:
| ADDITION |
The process that combines several numbers to obtain a single number whose value equals the total value of the numbers.
This operation is usually indicated by the "+" sign. |
| SUBTRACTION |
The inverse (the process that reverses an original process) of addition: this operation is the reduction of a number's value by the value of another number (or several numbers in sequence).
This operation is usually indicated by a " - " sign. |
| MULTIPLICATION |
The process that adds a number to itself a designated number of times; that is, 3 x 4 is merely four 3s added together or 3 + 3 + 3 + 3.
This operation is indicated by an "x" sign or sometimes by the centered period, " ." sign. It may also be understood when a symbol is juxtaposed to a number or another symbol (as in the operation fy, where the value is f x y. Multiplication is also shown if the symbol is next to an operation within parentheses, as in F(3 x 5) where the value is 3 times 5 times F. One always performs operations within parentheses first. |
| DIVISION |
This operation is the inverse of multiplication; that is, the value of the number is reduced into equal parts by a designated number.
This operation is indicated by a "÷" sign or by the slanted or horizontal line in a ratio or fraction, as indicated by "/" in the fraction 3/4. |
Remember: The operations of
multiplication and division are performed first in most statistical
packages, unless parentheses indicate a sub-operation to be performed
first.
Four basic mathematical operations
example
- Add: 3/7 + 2/9
- Subtract: 3/7 - 2/9
- Multiply: 3/7 x 2/9
- Divide: 3/7 ÷
2/9
Four basic mathematical operations
solution
ADDITION: the process that combines
values
| a/b + c/d |
= |
ad + cb
bd |
| 3/7 + 2/9 |
= |
(3 x 9) + (2 x 7)
(7 x 9) |
| |
= |
27 + 14
63 |
| |
= |
41
63 |
SUBTRACTION: the process that reduces
values
| a/b - c/d |
= |
ad - cb
bd |
| 3/7 - 2/9 |
= |
(3 x 9) - (2 x 7)
(27 x 9) |
| |
= |
7 - 14
63 |
| |
= |
13
63 |
MULTIPLICATION: the process that increases
the given number
| a/b x c/d |
= |
a x c
b x d |
| 3/7 x 2/9 |
= |
3 x 2
7 x 9 |
| |
= |
6
63 |
| |
= |
2
21 |
DIVISION: the process that reduces the
value equally
| a/b ÷ c/d |
= |
a/b x d/c |
| |
= |
a x d
b x c |
| 3/7 ÷ 2/9 |
= |
3 x 9
7 x 2 |
| |
= |
27
14 |
Addition
The simplest mathematical computation is
addition. Addition combines numbers to make a total called the sum. Of all
computations, however, addition, together with its inverse, subtraction,
is the source of most computation errors. For years, the IRS has listed
addition and subtraction mistakes as the leading cause of faulty returns.
For 2002 and beyond, companies must adopt a vesting schedule at least as
generous as those below for
employee 401(k) plans:
-
3-year cliff
vesting: 0% vesting for less than 3 years of service; 100% vesting
after 3 years
-
6-year
graded vesting: vesting begins in the employees second year of service;
it increases by 20% each year, until the employee is fully vested at the
beginning of the sixth year of employment
Six-year graded vesting proceeds like this:
| YEARS
OF SERVICE |
UNFORFEITABLE
PERCENTAGE |
| 2 |
20 |
| 3 |
40 |
| 4 |
60 |
| 5 |
80 |
| 6 |
100 |
Addition example
You are 40 years old and have worked for 5
years for your firm. As a participant in the firm's qualified pension
plan, what might your non-forfeitable vested pension percentage be in each
of the above plans?
Addition solution
Under the 2 different systems, you would be
vested as follows:
| 3-year cliff vesting |
100% |
| 6-year graded vesting |
80%
|
Subtraction
Subtraction is the inverse of addition. It
calls for the difference in the values of numbers.
Integration with Social Security benefits
is a perfect example of how human resource administrators utilize
subtraction:
| Individual retirement benefit from a retirement plan |
$600/month |
| Amount to be received from Social Security |
$400/month |
| Employer's contribution percentage |
37.5% |
| Employer's portion of $400 Social Security payment |
$150/month |
| FINAL RETIREMENT BENEFIT FROM PLAN |
$450/month |
Another example would be long-term
disability integration and net vs. gross pay computations.
Subtraction example
An employee who would receive
a final pension of 50% of last year's earnings in New York decides to
retire at age 60 rather than at age 62 (when he would be eligible for the
full 50% benefit). What might his percentage be? Remember that an actuarial reduction for early
retirement in a defined benefit plan is roughly 5% per year of the benefit
(e.g., 3% of a 60% defined benefit).
Subtraction solution
ACTUARIAL REDUCTION
5% of benefit per year = 50% x 5% = 2.5%
(i.e., .50 x .05 = .025 or 2.5%)
50% - 2.5% per year = 50% - (2.5 x 2)
= 50% - 5%
FINAL PENSION = 45%
Municipalities are often not
part of the Social Security System, so integration does not apply. In
some places, for example, retirement pay is based on a percentage of
"last year's earnings"; this includes overtime, hence, occasions have
arisen when retirement pay is almost at full last year's base pay.
Multiplication
Multiplication is the
computation process that simplifies addition. Factors are combined to give
a product.
COMPOUND INTEREST
The compounding of interest refers to the common savings account approach
that permits the following increases:
| Year 1: |
Interest is earned on the sum deposited. (e.g., at 4%, $10,000 would earn $400 in the first year.) |
| Year 2: |
Interest is earned on the original sum deposited (i.e., $10,000) and on the previous year's interest (i.e., $400 more) if the interest is left in the same account. At 4%, $10,000 would still earn $400 in the second year, but now the $400 from the previous year's interest would also be earning 4% interest to make a total of $416 earned in the second year. This makes a total of $10,816. |
| Year 3: |
This process continues indefinitely provided the accumulated interest is left in the same account. For example, the amount in the example above would begin the third year with $10,816 earning 4% on the entire amount. |
The formula reads:
Ending Sum = Initial Sum x (1 + Interest Rates)Years
e.g., $ 10,816 = $ 10,000 x (1 + .04)2 *
*It should be remembered
that the exponent (power) means that the operation or number should be
multiplied by itself that many times. In the example, therefore, the
process is (1.0 + . 04)(1.0 +.04). Always perform the operation in
parentheses first.
Multiplication example
It is the Year 2000 and the
average BA starting salary is $30,000. You predict these starting salaries
will increase at a rate of 9% per year. Using the compound interest
approach and a calculator, determine a starting salary for an MBA in the
year 2016.
Multiplication solution
COMPOUND INTEREST
|
YEAR |
PRINCIPAL ($) |
INTEREST AT 9% ($) |
|
2000 |
30,000 |
2,700 |
|
2001 |
32,700 |
2,943 |
|
2002 |
35,643 |
3,208 |
|
2003 |
38,851 |
3,497 |
|
2004 |
42,348 |
3,811 |
|
2005 |
45,159 |
4,154 |
|
2006 |
50,313 |
4,528 |
|
2007 |
54,841 |
4,936 |
|
2008 |
59,777 |
5,380 |
|
2009 |
65,167 |
5,864 |
|
2010 |
71,021 |
6,392 |
|
2011 |
77,413 |
6,967 |
|
2012 |
84,380 |
7,594 |
|
2013 |
91,974 |
8,278 |
|
2014 |
100,252 |
9,023 |
|
2015 |
109,275 |
9,835 |
|
2016 |
119,110 |
|
| Sum |
= Initial
Amount x (1 + Interest Rate)Years
= $30,000 x (1 + 0.09)(2016 - 2000)
= $30,000 x (1.09)16
= $30,000 x 3.970305
= $119,110 |
Division
Division is the inverse of
multiplication. It has the same relationship to multiplication that
subtraction has to addition. An inverse cancels the process of its
inverse. For example, if you begin with 3 and multiply it by 5 (3 x 5),
you need only divide the result (15) by 5 to once again have three.
In other words it reversed the original process.
In a division problem such as
15 ÷ 5 = 3, 15 is the dividend, 5 is called the divisor, and the result
(3) is the quotient.
Rule of 72
A very useful thing to
remember in human resource operations is called "The Rule of 72." If you
divide any interest rate into the number 72, your answer will be the
number of years it will take for a compound interest rate to double the
original sum.

Division example
It is the year 1984 and the
average MBA starting salary is $30,000. You predict starting salaries to
increase at a rate of 9% per year. Using the Rule of 72, what year will a
starting salary for an MBA double to be $60,000?
Division solution
Divide the percentage into 72.
Answer = the number of years
required to double the principal.
72 ÷
9 = 8
2000: $60,000
2016: $120,000
7.2% doubles money in ten
years
72 ÷ 7.2 = 10
12% doubles money in six
years
72 ÷ 12 = 6
If the inflation rate in 2000
is 12%, how much will a loaf of bread cost in the future?
| $4.00 |
in |
2006 |
| $8.00 |
in |
2012 |
| $16.00 |
in |
2018 |
| $32.00 |
in |
2024 |
| $64 |
in |
2030 |
The following sections will show you how to
use these mathematical operations for human resource planning, including
to determine:
-
present value
-
logarithms
-
averages
Present Value
Salary surveys deal with
money, and money accrues a certain value over time. In the traditional
sense, money can always be earning interest. The value of $1,000 today is
not necessarily what the value of $1,000 might be next year if that sum
can earn 10%.
Many human resource decisions
involve deferred payments. The collection of their values in a survey
would be misleading if they were reported only at their face values.
The computation of the value
of the present worth of any sum to be paid in "n" years can be computed
thus:

Present value example
A retirement plan promises to pay an
individual $10,000 in ten years. If present rates of interest are 10%,
what will that $10,000 be truly worth to the individual today?
Present value solution



Present value of compensation dollars depends
also on effective tax rates. It is important to remember that in the U.S.,
maximum tax rates were over 90% 50 years ago. Computations must all
estimate this effect -- a difficult task at best.
Logarithms
A logarithm is the exponent of the power to
which a fixed number must be raised to produce a given value. For example,
if the fixed number is 10 (the most common base), the logarithm of 1,000
is 3. You have to multiply 10 times itself three times (10 x 10 x 10) to
produce the desired result (1,000). The logarithm of 10,000 is four.
Logarithms are commonly used in human resource surveys, especially in graphs
that show salaries versus some
size dimension. The reason for their use is that they allow visual
comparison of data that may be quite dissimilar in size.
For example:
|
SALES ($) |
CHARACTERISTIC |
+ |
MANTISSA |
= |
LOG |
| 25,800,000,000 |
10 |
+ |
0.4116 |
= |
10.4116 |
| 258,000,000 |
8 |
+ |
0.4116 |
= |
8.4116 |
| 2,580,000 |
6 |
+ |
0.4116 |
= |
6.4116 |
| 25,800 |
4 |
+ |
0.4116 |
= |
4.4116 |
Companies of the above sizes could all be
shown on the same graph with divisions from 1 to 10.
Working with logarithms requires the exercise
of manipulating the exponents (power of the numbers).
Logarithms at a base of 10 are best
illustrated by:
-
10 = 101 = 1
-
100 = 102 = 2
Dividing or multiplying with logarithms is
like dividing or multiplying with other exponents. To multiply, you
add the exponents. To
divide you subtract the exponents.
For example:
103 x 104 = 107
OR
108 ÷ 102 = 106
Logarithm example
Compute the average sales of the four
companies above by using the logs. (The log of four is 0.6021.)
Logarithm solution
If 10 were divided by 4, one would find a
logarithm of:
log of 10 = 1
log of 4 = 0.6021
log of 10 ÷ log of 4 = 1 - 0.6021 = 0.3979
Looking up the value of 0.3979 in
Table 2 one finds
2.5. With a "0" characteristic, one moves the decimal place from the
left one digit -- that is, 2.5 (1.3979).
Average Sales Size is:
25,800,000,000
258,000,000
2,580,000
25,800
26,060,605,800
The log of which (counting digits and using
Table 2)
10.4160
- .6021
9.8139
(log of 4)
9.8139 = $6,515,000,000
Averages
As shown in the preceding example, the mean or
average of a distribution is defined as the sum of the values of the
variables in the distribution divided by the number of observations in
that distribution. When the distribution is a sample:
AVERAGE = Sum of Variables / Number in Sample
| Remember: |
An observation is a discrete event to which the value of a variable has been assigned; several observations can have the same value.
A variable is the aspect of the world being observed, to which value has been assigned. |
SAMPLE
50
40
39
39
37
36
34
28
26
25
24
21
18
15
12
12
10
8
7
529 |
|
The
number of observations in the sample is 20. (Observations could be
number of employees in different departments, number of days worked
overtime, etc. -- whatever can be defined as being distinct and separate.)
The sum of the variables (i.e., the values of each variable) is 529. (For
instance, one department may have 40 employees, another 39, another 28;
the 28 variables observed is the number of employees, the 20 observations
are the departments.)
Average = 529/20
Average = 26.45
Mean = Average
Mean = 26.45
|
Average example
You conduct a survey of controllers in
companies in a certain industry and find the following salaries being
paid: $14,000, $15,000, $15,000, $16,000, $18,000, $21,000, $28,000, and
$42,000. What is the average salary?
Average solution
AVERAGE = Sum of Variables / Number in Sample
Sum of Variables = $14,000 + $15,000 + $15,000
+ $16,000 + $18,000 + $21,000 + $28,000 + $42,000 = $169,000
Number in Sample = 8
Average = $169,000 / 8 = $21,125
Medians
The median is the midpoint of a distribution.
Half of the observations in a distribution are above the median; the other
half are below.
When the sample or population consists of an
even number of observations, the true median may lie halfway between the
two middle observations.
|
TABLE A |
TABLE B |
| 40 |
36 |
|
39 |
33 |
|
39 |
32 |
|
37 |
29 |
|
36 |
28 |
|
36 |
27 |
|
34 |
27 |
|
30 |
27 |
|
28 |
26 |
|
26 |
24 |
|
25 |
22 |
|
24 |
21 |
|
21 |
20 |
|
18 |
14 |
|
15 |
14 |
|
12 |
12 |
|
12 |
12 |
|
10 |
11 |
|
8 |
7 |
|
THE MEDIAN IS 26 |
THE MEDIAN IS 24 |
Median example
You conduct a survey of controllers' salaries
in companies in a certain industry and find these: $14,000, $15,000,
$15,000, $15,000, $16,000, $16,000, $18,000, $21,000, $28,000, S42,000.
What is the median salary?
Median solution
Calculation of the median:
$14,000
$15,000
$15,000
$15,000
$16,000
$16,000
$18,000
$21,000
$28,000
$42,000
- Count the number of salaries n = 10
- Count up halfway or down halfway (5)
- The median salary is halfway between $16,000 and $18,000
A general rule in statistics is to round up on
odd counts from the lower observation ($16,000); but because this
is the real world, we would suggest utilizing the real median which is
$17,000, a value at the halfway point which is at an equal distance from
each variable.
However, some texts state that it must be an
actual observation (in this case, an actual salary), which means that it
would not have been $17,000.
Weighted Average
A popular survey gives the following
definition of "weighted average."
The average weekly salary reported by a
company for a given position is multiplied by the number of employees in
the job. The results are totaled for all companies reporting the
position, and then divided by the total number of incumbents.
Another survey defines weighted averages a "the
distribution of salaries is reviewed by deleting the top 25% and bottom
25% of the sample. The average is then computed from the interquartile
range."
The point to note, like the rounding of
medians, is that in salary surveys this term "weighted average" may have
different meanings for different surveys. Most commonly, the first
definition is used.
The reason for weighting averages is that the
result represents the average of a total population and not just a subset. The equation for this procedure reads:

Where:
a, b, c are averages of measurements
N1, N2, N3 are numbers of measurements
Weighted average example
Two companies reported the average salary for a similar position as follows:
Company A
Incumbents: 6
Average Salary: $10.00
Company B
Incumbents: 2
Average Salary: $8.50
What is the weighted average for this position? How does it compare to simply averaging the two surveys?
Solution
| |
Company A |
Company B |
| Average |
$10.00 |
$8.50 |
| Sample Size |
6 |
2 |
| Weighted Average |
(10.00 x 6) + (8.50 x 2) = 77.00/8 = 9.63 |
| Simple Average |
10.00 + 8.50 = 18.50 = 9.25 |
Modes
The mode is that category of the distribution
that contains observations that appear with the greatest frequency. That is, the most frequent set of measurements is the mode of the
distribution. In grouped data, the mode is associated with the
midpoint of the category that has the greatest frequency.
The category with the greatest frequency
concentration often tends to be located at or near the center of a
distribution. However, this is not always the case; thus, as a
measurement, the mode leaves much to be desired.
| SAMPLE |
|
| 40 |
|
| 39 |
The
mode is 39. |
| 39 |
This
is the observation with the greatest frequency. |
| 39 |
|
| 37 |
|
| 36 |
|
| 34 |
|
| 30 |
|
| 28 |
|
| 28 |
|
| 26 |
|
| 25 |
|
| 24 |
|
| 21 |
|
| 18 |
|
| 15 |
|
| 12 |
|
| 12 |
|
| 10 |
|
| 8 |
|
Mode example
You conduct a survey of controllers' salaries
in a certain industry and find the following salaries:
$14,000
$15,000
$15,000
$15,000
$16,000
$16,000
$18,000
$21,000
$28,000
$42,000
What is the mode salary?
Mode solution
The highest number of occurrences of any
single event -- in this case, 3 -- is $15,000.
Therefore, $15,000 is the mode.
| $14,000 |
1 occurrence |
| $15,000 |
3
occurrences |
| $15,000 |
| $15,000 |
| $16,000 |
2
occurrences |
| $16,000 |
| $18,000 |
1 occurrence |
| $21,000 |
1 occurrence |
| $28,000 |
1 occurrence |
| $42,000 |
1 occurrence |
Percentages
Percentages are the most commonly used form of
fractions. Computed in 100ths, they allow a representation of a
fraction in terms of 100s or "cents" (from the Latin), providing the user
with a basis for making comparisons.
Percentiles
Percentiles are arbitrarily selected units
determined by dividing a whole into a distribution of 100 equal parts.
A percentile distribution is based on the number of observations
constituting a given percentage of the total number of observations in the
distribution, irrespective of category; percentiles are frequently used to
determine what proportion of the distribution falls below a given level.

Percentile example
You have started a company and have hired an
administrative assistant at $28,000. He is the tenth highest paid of
123 secretaries. His salary is at what percentile?
Percentile solution
The correct answer is "91st percentile."
| Rank |
10th highest of 123 |
| Standing |
Maximum minus ranking
123 - 10 = 113 |
| Percentage |
(Standing divided by maximum) x 100
(113 / 123) x 100
0.9187 x 100
91.87 |
| Percentile |
91th percentile (In determining test scores, it is a common practice to drop the decimal place and round down.) |
Axes
The bottom line of a graph (the horizontal
line) is known as the base line for as the "horizontal axis." By
convention, mathematicians refer to it as the x-axis.
The line perpendicular to the x-axis (usually
at the left) is known as the "vertical axis" or, again according to
convention, the y-axis.
In equations, these axes are often defined in
the form of:
value of y = value of x(another value) + a
constant
That is: y = mx + b
Axis example
You conduct a survey of typist test scores and
find the following results: 100, 85, 70, 75, 50. Correspondingly, you find
the age of each typist to be 60, 50, 40, 30, 20. What would be the x-axis
if you were to plot this data?
Axis solution
Either salaries or years of experience could
serve as the x-axis.
Example:
|
AGE |
SCORE |
|
60 |
100 |
|
50 |
85 |
|
40 |
70 |
|
30 |
75 |
|
20 |
50 |

Slope and Intercept
An equation is most often expressed in the
form:
y = mx + b
The slope is the change in the value of y that
corresponds directly to a change in the value of x.

An equation is useful because it describes any
value of y if you know any value of x.
Slope and intercept example
Draw a graph that shows the following three
lines:
-
The first line should show where the "x" value always equals the "y"
value.
-
The second line should show where the "y"
value is 10 less than the "x" value and an additional 10% more than the
"x" value.
-
The third line should show the "y" value that
is constant regardless of the value of "x."
Slope and intercept solution
| The first line should show where the "x" value always equals the "y" value. |
y = 1x + 0
y = x |
| The second line should show where the "y" value is 10 less than the "x" value and an additional 10% more than the "x" value. |
y = (x - 10) 0.10
y = 0.1x - 1 |
| The third line should show the "y" value that is constant regardless of the value of "x." |
y = 0x + constant
y = constant |

Calculations of Equations
The equation of a straight line is:
y = mx + b
When given any two points on a line, one can
calculate an equation to find any other points on the same line as
follows:
| Point 1 (x1y1) |
Point 2 (x2y2) |
| Slope (m) |
 |
| Intercept (b) |
y1 - mx1 |
| OR |
|
| Intercept (b) |
y2 - mx2 |
Calculations of Equations Example
You have seen that a 60-year-old typist
scored 100, while a 20-year-old typist scored 50 on a typing test. Calculate the equation for the line that passes through these points.
Calculations of Equations Solution
Point 1 (60,100)
Point 2 (20,50)
| Slope
(m) |
 50
- 100
20 - 60
-
50
- 40
|
|
Slope
(m) |
=
1.25 |
| Intercept (b) |
= y1 -
mx1 =
100 - (1.25 x 60)
=
100 - 75
|
| Intercept
(b) |
=
25 |
The equation for the line that passes through
(60,100) and (20,50) is:
y = 1.25x + 25
To check, review y2 and x2.
y2 = mx2 + b
50 = (1.25) (20) + 25
50 = 50
Correct
 |
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| 1 |
David J. Thomsen, Quantitative Methods Used in Personnel, (Compensation Institute, 1976). |
| 2 |
David J. Thomsen, Original Certification Course in Quantitative Methods, (ACA, 1978). |
|